To solve the equation \( 3x^2 = 21 \), we can start by isolating \( x^2 \):
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Divide both sides by 3: \[ x^2 = \frac{21}{3} \] \[ x^2 = 7 \]
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Next, we take the square root of both sides: \[ x = \pm \sqrt{7} \]
This implies that there are two solutions: \( \sqrt{7} \) and \( -\sqrt{7} \).
Therefore, the number of solutions in the solution set for the equation \( 3x^2 = 21 \) is two.