There are two reactions here.
1) Strontium is an active metal what will react with water, forming Strontium hydroxide (aq), and releasing hydrogen gas in the form of bubbles.
Sr + 2H+ + 2OH- >> Sr++ + 2OH- + H2 (g)
2) The second reaction is that Strontium will replace the Copper(II) ions in the cupric nitrate, precipating copper
I will be happy to critique your thinking on that reaction.
Write the net ionic formula.
A bar of strontium metal is immersed in a 1.0 M copper (II) nitrate solution.
How do I go about doing this?
4 answers
I believe I am to write the second one down. Does the 1.0 M even come into play in this problem?
No, the strength of the copper(II) solution is not used. It must be something, in order to plate out Cu metal, but the actual number, unless you were calculating the amount of copper plated out, is not needed.
Ok, I thought that was just thrown in to test us. That's what I needed to know. Let me give it another go...
1 answer