Question

Solve the radical equation.

Vx + 3 - 9 = -5
A. X = 5
B. X = 11
C. X = 7
D. X = 13

Answer 1

To solve the equation \( \sqrt{x} + 3 - 9 = -5 \), we first simplify it:

\[
\sqrt{x} + 3 - 9 = -5
\]
This simplifies to:

\[
\sqrt{x} - 6 = -5
\]

Next, we add 6 to both sides:

\[
\sqrt{x} = -5 + 6
\]

This gives us:

\[
\sqrt{x} = 1
\]

Now, we square both sides to solve for \( x \):

\[
(\sqrt{x})^2 = 1^2
\]

This yields:

\[
x = 1
\]

However, \( x = 1 \) is not among the answer choices provided (5, 11, 7, 13). Let's double-check to ensure we've solved correctly.

The original equation simplifies correctly to \( \sqrt{x} = 1 \) leading to \( x = 1 \).

Since x = 1 does not match the answer options (A, B, C, D), it seems there might be a misunderstanding or error in the provided options or the equation itself.

Would you like to verify the options or the equation?