Asked by danni
Write a polynomial function that has the zeros 2, -2, and -1 and has a leading coefficient of 1. Then graph the function to show that 2, -2, and -1 are solutions.
Answers
Answered by
drwls
Multiply this out:
(x-2)(x+2)(x+1) = (x^2-4)(x+1)
= x^3 +x^2 -4x -4
(x-2)(x+2)(x+1) = (x^2-4)(x+1)
= x^3 +x^2 -4x -4
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