Asked by danni

Write a polynomial function that has the zeros 2, -2, and -1 and has a leading coefficient of 1. Then graph the function to show that 2, -2, and -1 are solutions.
Answered by drwls
Multiply this out:

(x-2)(x+2)(x+1) = (x^2-4)(x+1)
= x^3 +x^2 -4x -4