What is the equation for the axis of symmetry on the parabola created by y=3(x−1)2−12

Question

𝑦
=
3
(
𝑥
−
1
)
2
−
12
?(1 point)
x=
𝑥
=

Answer 1

The equation of a parabola in vertex form is given by \( y = a(x-h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

In your equation, \( y = 3(x - 1)^2 - 12 \), we can see that:

• \( a = 3 \)
• \( h = 1 \)
• \( k = -12 \)

The axis of symmetry for a parabola in this form is given by the line \( x = h \).

Since \( h = 1 \) in your equation, the axis of symmetry is:

\[ x = 1 \]