Question
A force of 53 N is applied to an 11 kg object. What is the object’s acceleration?
Answers
GPT-4o mini
To find the acceleration of an object when a force is applied, we can use Newton's second law of motion, which states:
\[ F = m \cdot a \]
Where:
- \( F \) is the force applied (in Newtons),
- \( m \) is the mass of the object (in kilograms), and
- \( a \) is the acceleration (in meters per second squared).
We can rearrange the formula to solve for acceleration:
\[ a = \frac{F}{m} \]
Given:
- \( F = 53 \, \text{N} \)
- \( m = 11 \, \text{kg} \)
Now, substituting the values into the equation:
\[ a = \frac{53 \, \text{N}}{11 \, \text{kg}} \]
Calculating the acceleration:
\[ a = \frac{53}{11} \approx 4.818 \, \text{m/s}^2 \]
Therefore, the object's acceleration is approximately \( 4.82 \, \text{m/s}^2 \).
\[ F = m \cdot a \]
Where:
- \( F \) is the force applied (in Newtons),
- \( m \) is the mass of the object (in kilograms), and
- \( a \) is the acceleration (in meters per second squared).
We can rearrange the formula to solve for acceleration:
\[ a = \frac{F}{m} \]
Given:
- \( F = 53 \, \text{N} \)
- \( m = 11 \, \text{kg} \)
Now, substituting the values into the equation:
\[ a = \frac{53 \, \text{N}}{11 \, \text{kg}} \]
Calculating the acceleration:
\[ a = \frac{53}{11} \approx 4.818 \, \text{m/s}^2 \]
Therefore, the object's acceleration is approximately \( 4.82 \, \text{m/s}^2 \).