make a sketch, you should have a right-angled triangle with sides 2 and 3 and the angle of 90° between the 2 and 3.
Mentally you should be able to calculate the hypotenuse to be √13
That would be the time to get back.
Find the angle at the top of the triangle by
tan A = 2/3
A = 33.69°
By laying a NSEW direction pattern over point A, you would have a bearing of 168.69°
Can someone help me with this problem, please? Thanks!!
"A ship leaves port and sails for 2 hours northeast and then 3 hours northwest. If the speed remains constant, what course should the ship take home?"
1 answer
3 answers