Solve the following equation with a rational exponent: 5x4/3=80.

1 answer

To solve the equation \( 5x^{4/3} = 80 \), we will first isolate \( x^{4/3} \).

  1. Divide both sides by 5:

\[ x^{4/3} = \frac{80}{5} \]

\[ x^{4/3} = 16 \]

  1. Now we can eliminate the rational exponent by raising both sides to the reciprocal of \( \frac{4}{3} \), which is \( \frac{3}{4} \):

\[ x = 16^{\frac{3}{4}} \]

  1. Next, we need to compute \( 16^{\frac{3}{4}} \). First, we can break it down:

\[ 16^{\frac{3}{4}} = (16^{\frac{1}{4}})^3 \]

  1. Since \( 16 = 2^4 \), we have:

\[ 16^{\frac{1}{4}} = (2^4)^{\frac{1}{4}} = 2^{4 \cdot \frac{1}{4}} = 2^1 = 2 \]

  1. Now, substituting this back in, we get:

\[ x = (2)^3 = 8 \]

Thus, the solution to the equation \( 5x^{4/3} = 80 \) is:

\[ \boxed{8} \]

Similar Questions
  1. Properties of Rational Exponents Quick Check4 of 54 of 5 Items Question Solve the following equation with a rational exponent:
    1. answers icon 1 answer
  2. Properties of Rational Exponents Quick Check5 of 55 of 5 Items Question Solve the following equation with a rational exponent:
    1. answers icon 1 answer
    1. answers icon 5 answers
    1. answers icon 1 answer
more similar questions