Y^2-4y+3/y^2-9*4y+12/y2-2y+1=

Question

16y^4+36/2y^5+8
check this please

Answer 1

oh my

(y^2 - 4y + 3)/(y^2 - 9) * (4y + 12)/(y^2 - 2y + 1)
= (y-3)(y-1)/[(y+3)(y-3)] * 4(y+3)/[(y-1)(y-1)]
= 4/(y-1) y ≠ ±1, ±3