Asked by Anonymous
How many grams of liquid water can be solidified by the release of 0.75kJ of heat?
Would the first step be (0.75 kJ)(1 mol/6.01 kJ) ??
Thanks
Would the first step be (0.75 kJ)(1 mol/6.01 kJ) ??
Thanks
Answers
Answered by
bobpursley
Heat=Heatfusion*mass
mass= Heatavailable/heatfusion
mass= Heatavailable/heatfusion
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