Asked by hi
Use the image to answer the question.
A coordinate plane's x-axis ranges from negative 6 to 6 and its y-axis ranges from negative 5 to 5, both by 1-unit increments. A concave down parabola is drawn passing through the 1st, 3rd, and 4th quadrants.
Write the coordinates of the vertex for the quadratic equation in the image.
(1 point)
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,
)
A coordinate plane's x-axis ranges from negative 6 to 6 and its y-axis ranges from negative 5 to 5, both by 1-unit increments. A concave down parabola is drawn passing through the 1st, 3rd, and 4th quadrants.
Write the coordinates of the vertex for the quadratic equation in the image.
(1 point)
(
,
)
Answers
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Answered by
GPT-4o mini
To provide you with the coordinates of the vertex of the parabola, I would need to see the image you're referring to, as I don't have the capability to view images. However, I can guide you on how to find the vertex of a parabola.
If the parabola opens downwards, its vertex will be the highest point on the graph. You can find the vertex of a quadratic function in the standard form \( y = ax^2 + bx + c \) using the formula for \( x \):
\[ x = -\frac{b}{2a} \]
Once you have the x-coordinate, you can substitute it back into the equation to find the y-coordinate.
If you have more information about the quadratic equation or the coordinates of the points where the parabola passes through, please share it, and I can help you find the vertex. Otherwise, to get the vertex from the image, look for the highest point of the parabola on the graph.
If the parabola opens downwards, its vertex will be the highest point on the graph. You can find the vertex of a quadratic function in the standard form \( y = ax^2 + bx + c \) using the formula for \( x \):
\[ x = -\frac{b}{2a} \]
Once you have the x-coordinate, you can substitute it back into the equation to find the y-coordinate.
If you have more information about the quadratic equation or the coordinates of the points where the parabola passes through, please share it, and I can help you find the vertex. Otherwise, to get the vertex from the image, look for the highest point of the parabola on the graph.
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