To find angle \( b \), we need to use the properties of exterior angles of triangles. The exterior angle of a triangle is equal to the sum of the two opposite interior angles.
Let's denote:
- The top angle as \( A \),
- The left corner square's angle as \( 90^\circ \) (since it's a square),
- The right corner angle as \( b \).
If we are considering a triangle where angle \( A \) and the left angle (which is \( 90^\circ \)) form an exterior angle with angle \( b \), we can set up the following equation using the exterior angle theorem:
\[ A = 90^\circ + b \]
We do not have the value of \( A \) directly, but the question provides no further context about its value. Since we are looking for \( b \), we will solve for it:
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If we assume \( A=92^\circ \): \[ 92^\circ = 90^\circ + b \] \[ b = 92^\circ - 90^\circ = 2^\circ \]
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Assume \( A=38^\circ \): \[ 38^\circ = 90^\circ + b \] \[ b = 38^\circ - 90^\circ = -52^\circ \quad \text{(not valid)} \]
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Assume \( A=232^\circ \): \[ 232^\circ = 90^\circ + b \] \[ b = 232^\circ - 90^\circ = 142^\circ \]
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Assume \( A=52^\circ \): \[ 52^\circ = 90^\circ + b \] \[ b = 52^\circ - 90^\circ = -38^\circ \quad \text{(not valid)} \]
Thus, the only valid option from the provided choices, taking into account the understanding of how the exterior angle \( b \) behaves based on a comparison with \( A \), is \( 52^\circ \) as it doesn't present a valid angle calculation.
Therefore, the answer is:
O 52°.
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