Question

The top points angle is a
The left corners one is a square
The right corners angle is b

Use the properties of exterior angles of triangles to find angle b.

(1 point)

Ο 92°

O 38°

O 232°

Ο 52°

Answer 1

To find angle \( b \), we need to use the properties of exterior angles of triangles. The exterior angle of a triangle is equal to the sum of the two opposite interior angles.

Let's denote:
- The top angle as \( A \),
- The left corner square's angle as \( 90^\circ \) (since it's a square),
- The right corner angle as \( b \).

If we are considering a triangle where angle \( A \) and the left angle (which is \( 90^\circ \)) form an exterior angle with angle \( b \), we can set up the following equation using the exterior angle theorem:

\[
A = 90^\circ + b
\]

We do not have the value of \( A \) directly, but the question provides no further context about its value. Since we are looking for \( b \), we will solve for it:

1. If we assume \( A=92^\circ \):
\[
92^\circ = 90^\circ + b
\]
\[
b = 92^\circ - 90^\circ = 2^\circ
\]

2. Assume \( A=38^\circ \):
\[
38^\circ = 90^\circ + b
\]
\[
b = 38^\circ - 90^\circ = -52^\circ \quad \text{(not valid)}
\]

3. Assume \( A=232^\circ \):
\[
232^\circ = 90^\circ + b
\]
\[
b = 232^\circ - 90^\circ = 142^\circ
\]

4. Assume \( A=52^\circ \):
\[
52^\circ = 90^\circ + b
\]
\[
b = 52^\circ - 90^\circ = -38^\circ \quad \text{(not valid)}
\]

Thus, the only valid option from the provided choices, taking into account the understanding of how the exterior angle \( b \) behaves based on a comparison with \( A \), is **\( 52^\circ \)** as it doesn't present a valid angle calculation.

### Therefore, the answer is:
**O 52°**.