To create an equation that represents the number of magazines Sheila has read after \( x \) weeks, we can follow the same structure we used for Judy. Initialize the number of magazines Sheila has read:
- Sheila has read 10 magazines initially and reads 5 more each week.
Thus, the equation for the number of magazines Sheila has read, \( y \), after \( x \) weeks would be:
\[ y = 10 + 5x \]
Summary of the Equations:
- Judy: \( y = 5 + 5x \)
- Sheila: \( y = 10 + 5x \)
Finding When They Have Read the Same Number of Magazines
Now let's find out after how many weeks \( x \) they will have read the same number of magazines:
We set their equations equal to each other:
\[ 10 + 5x = 5 + 5x \]
To solve for \( x \), we can subtract \( 5x \) from both sides:
\[ 10 = 5 \]
Since this statement is not true, it indicates that they will never have read the same number of magazines as both are reading at the same rate of 5 magazines per week, but Sheila started with 5 more magazines than Judy.
Table for Judy
To complete the table for Judy's magazines after 3, 5, and 7 weeks:
-
At 3 weeks:
\( y = 5 + 5(3) = 5 + 15 = 20 \) -
At 5 weeks:
\( y = 5 + 5(5) = 5 + 25 = 30 \) -
At 7 weeks:
\( y = 5 + 5(7) = 5 + 35 = 40 \)
Completed Table for Judy:
| Weeks (x) | Magazines (y) | |-----------|----------------| | 3 | 20 | | 5 | 30 | | 7 | 40 |
Graphing Points
The points to graph will be:
- (3, 20)
- (5, 30)
- (7, 40)
Summary
- Judy’s Equation: \( y = 5 + 5x \)
- Sheila’s Equation: \( y = 10 + 5x \)
- They will never have read the same number of magazines given their current rates.