Question

Solve x3≥12 .(1 point)

Answer 1

To solve the inequality \( x^3 \geq 12 \), we first want to isolate \( x \).

1. Start by taking the cube root of both sides:

\[
x \geq \sqrt[3]{12}
\]

2. Now, calculate the cube root of 12. The exact cube root can be left in radical form or approximated:

\[
\sqrt[3]{12} \approx 2.289
\]

Thus, the solution to the inequality \( x^3 \geq 12 \) is:

\[
x \geq \sqrt[3]{12} \quad \text{or approximately} \quad x \geq 2.289
\]

In interval notation, the solution can be expressed as:

\[
[ \sqrt[3]{12}, \infty )
\]