Question

A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point)
Responses

0 J
0 J

24,600 J
24,600 J

18.2 J
18.2 J

705 J

Answer 1

To calculate the work done, you can use the formula:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

where:
- Work is in joules (J),
- Force is in newtons (N),
- Distance is in meters (m),
- \( \theta \) is the angle between the force and the direction of motion.

If the force is applied in the direction of the motion (which is the typical assumption for such problems unless stated otherwise), then \( \theta = 0 \) degrees, and \( \cos(0) = 1 \).

Using the values provided:
- Force = 36.8 N,
- Distance = 668 m,

The work done can be calculated as:

\[ \text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} \]

Now, calculate it:

\[ \text{Work} = 36.8 \times 668 = 24,617.6 \, \text{J} \]

Rounding it, we can approximate it as:

\[ \text{Work} \approx 24,600 \, \text{J} \]

So, the correct response is:

**24,600 J**