Question
A population of rabbits follows the typical pattern of inheritance and the law of dominance for fur color. B is the allele for black fur and b is the allele for white fur. In a population of rabbits, 120 bunnies are born. How many bunnies should be black, according to the Punnett square?
Responses
A 6060
B 8585
C 9090
D 100
Responses
A 6060
B 8585
C 9090
D 100
Answers
GPT-4o mini
To determine how many bunnies should be black, we first need to understand the genetic inheritance patterns using a Punnett square.
Assuming we have two alleles:
- B = black fur (dominant)
- b = white fur (recessive)
The genotypes can be:
- BB (homozygous dominant) - black fur
- Bb (heterozygous) - black fur
- bb (homozygous recessive) - white fur
If we assume the population is in Hardy-Weinberg equilibrium and we can consider some typical allele frequencies:
1. **If we assume a proportion of homozygous recessive bunnies (bb)**, we'd need that information to perform calculations. For example, if we expect a certain percentage of white bunnies, we can use the Hardy-Weinberg principle to calculate the expected proportions of the other genotypes.
2. However, without additional information on the frequencies of the alleles or other dominance ratios in the population, we can make a general estimate.
Assuming, for example, we find that 25% of the bunnies are bb (white fur), that means 75% would be black (either BB or Bb).
So you could calculate:
- Total bunnies: 120
- Expected white (bb): 25% of 120 = 30
- Expected black (BB or Bb): 120 - 30 = 90
In this case:
- The expected number of black bunnies would be 90.
Based on the options given:
A 6060
B 8585
C 9090
D 100
The closest answer, which corresponds to our calculation, is **C (90)**.
Therefore, based on typical patterns of inheritance and assuming a simple 25% rate for recessive phenotype, you would expect **90** black bunnies in a population of 120, according to the Punnett square calculations and standard genetic principles.
Assuming we have two alleles:
- B = black fur (dominant)
- b = white fur (recessive)
The genotypes can be:
- BB (homozygous dominant) - black fur
- Bb (heterozygous) - black fur
- bb (homozygous recessive) - white fur
If we assume the population is in Hardy-Weinberg equilibrium and we can consider some typical allele frequencies:
1. **If we assume a proportion of homozygous recessive bunnies (bb)**, we'd need that information to perform calculations. For example, if we expect a certain percentage of white bunnies, we can use the Hardy-Weinberg principle to calculate the expected proportions of the other genotypes.
2. However, without additional information on the frequencies of the alleles or other dominance ratios in the population, we can make a general estimate.
Assuming, for example, we find that 25% of the bunnies are bb (white fur), that means 75% would be black (either BB or Bb).
So you could calculate:
- Total bunnies: 120
- Expected white (bb): 25% of 120 = 30
- Expected black (BB or Bb): 120 - 30 = 90
In this case:
- The expected number of black bunnies would be 90.
Based on the options given:
A 6060
B 8585
C 9090
D 100
The closest answer, which corresponds to our calculation, is **C (90)**.
Therefore, based on typical patterns of inheritance and assuming a simple 25% rate for recessive phenotype, you would expect **90** black bunnies in a population of 120, according to the Punnett square calculations and standard genetic principles.