When 1.33 g of a nonpolar solute was dissolved in 50.0 g of phenol, the latter's freezing point was lowered by 1.454°C. Calculate the molar mass of the solute. The kf of phenol is 7.27 (K·kg)/mol.

What is the normal boiling point of an aqueous solution that has a freezing point of -1.04°C?
The kf of water is 1.86 (K·kg)/mol and the kb of water is 0.51 (K·kg)/mol

I am having a diffculty time with coming up with the answer when dealing with freezing and boiling points? Thank you for the help!