To analyze the equation \( y = -5(x)^2 + 1 \), let's identify important features of the graph.
-
Form of the quadratic equation: The equation is in the standard form \( y = ax^2 + bx + c \), where in this case, \( a = -5 \), \( b = 0 \), and \( c = 1 \).
-
Vertex: The vertex of a quadratic equation \( y = ax^2 + bx + c \) can be found using the formula: \[ x = -\frac{b}{2a} \] Substituting \( b = 0 \) and \( a = -5 \): \[ x = -\frac{0}{2 \times -5} = 0 \] To find the \( y \)-coordinate of the vertex, substitute \( x = 0 \) back into the equation: \[ y = -5(0)^2 + 1 = 1 \] Thus, the vertex is at \( (0, 1) \).
-
Direction of the parabola: Since \( a = -5 \), which is negative, the parabola opens downwards.
Now, let's summarize:
- The vertex is at \( (0, 1) \).
- The parabola opens downwards.
Based on the response options given, the correct statements are:
- None of the vertex options are correct, since they all suggest a vertex at \( (0, 0) \), \( (1, 0) \), or \( (-1, 0) \).
- The correct statement about the direction of the parabola is: The parabola will open downwards.
So, the final answer is that the parabola will open downwards.