Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Graph the equation y=−5(x)2+1 . Which of the following statements about the graph is correct?(1 point) Responses The parabola w...Question
Graph the equation y=−5(x)2+1 . Which of the following statements about the graph is correct?(1 point) Responses The parabola will have a vertex at (0,0) . The parabola will have a vertex at left parenthesis 0 comma 0 right parenthesis . The parabola will have a vertex at (1,0) . The parabola will have a vertex at left parenthesis 1 comma 0 right parenthesis . The parabola will have a vertex at (−1,0) . The parabola will have a vertex at left parenthesis negative 1 comma 0 right parenthesis . The parabola will open downwards. The parabola will open downwards.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To analyze the equation \( y = -5(x)^2 + 1 \), let's identify important features of the graph.
1. **Form of the quadratic equation**: The equation is in the standard form \( y = ax^2 + bx + c \), where in this case, \( a = -5 \), \( b = 0 \), and \( c = 1 \).
2. **Vertex**: The vertex of a quadratic equation \( y = ax^2 + bx + c \) can be found using the formula:
\[
x = -\frac{b}{2a}
\]
Substituting \( b = 0 \) and \( a = -5 \):
\[
x = -\frac{0}{2 \times -5} = 0
\]
To find the \( y \)-coordinate of the vertex, substitute \( x = 0 \) back into the equation:
\[
y = -5(0)^2 + 1 = 1
\]
Thus, the vertex is at \( (0, 1) \).
3. **Direction of the parabola**: Since \( a = -5 \), which is negative, the parabola opens downwards.
Now, let's summarize:
- The vertex is at \( (0, 1) \).
- The parabola opens downwards.
Based on the response options given, the correct statements are:
- **None of the vertex options are correct**, since they all suggest a vertex at \( (0, 0) \), \( (1, 0) \), or \( (-1, 0) \).
- The correct statement about the direction of the parabola is: **The parabola will open downwards.**
So, the final answer is that the parabola will open downwards.
1. **Form of the quadratic equation**: The equation is in the standard form \( y = ax^2 + bx + c \), where in this case, \( a = -5 \), \( b = 0 \), and \( c = 1 \).
2. **Vertex**: The vertex of a quadratic equation \( y = ax^2 + bx + c \) can be found using the formula:
\[
x = -\frac{b}{2a}
\]
Substituting \( b = 0 \) and \( a = -5 \):
\[
x = -\frac{0}{2 \times -5} = 0
\]
To find the \( y \)-coordinate of the vertex, substitute \( x = 0 \) back into the equation:
\[
y = -5(0)^2 + 1 = 1
\]
Thus, the vertex is at \( (0, 1) \).
3. **Direction of the parabola**: Since \( a = -5 \), which is negative, the parabola opens downwards.
Now, let's summarize:
- The vertex is at \( (0, 1) \).
- The parabola opens downwards.
Based on the response options given, the correct statements are:
- **None of the vertex options are correct**, since they all suggest a vertex at \( (0, 0) \), \( (1, 0) \), or \( (-1, 0) \).
- The correct statement about the direction of the parabola is: **The parabola will open downwards.**
So, the final answer is that the parabola will open downwards.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.