Question
Question 1 A)What is the mathematical relationship between force and work?(1 point) Responses W=FdW=Fdcap w is equal to cap f over d W=F×aW=F×aW=F×aW=F×a W=F×dW=F×dW=F×dW=F×d W×d=FW×d=FW×d=FW×d=F Question 2 A)If W=F×dW=F×d, which of the following equations shows work being calculated using the correct units?(1 point) Responses 113 J=(17.4 N)×(6.51 m)113 J=(17.4 N)×(6.51 m)113 J=(17.4 N)×(6.51 m)113 J=(17.4 N)×(6.51 m) 113 N=(17.4 J)×(6.51 ft)113 N=(17.4 J)×(6.51 ft)113 N=(17.4 J)×(6.51 ft)113 N=(17.4 J)×(6.51 ft) 113 J=(17.4 N)×(6.51 ft)113 J=(17.4 N)×(6.51 ft)113 J=(17.4 N)×(6.51 ft)113 J=(17.4 N)×(6.51 ft) 113 N=(17.4 J)×(6.51 m)113 N=(17.4 J)×(6.51 m)113 N=(17.4 J)×(6.51 m)113 N=(17.4 J)×(6.51 m) Question 3 A)A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point) Responses 58.4 J 58.4 J 58.1 J 58.1 J 56.1 J 56.1 J 55.8 J 55.8 J Question 4 A)A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point) Responses 18.2 J 18.2 J 705 J 705 J 0 J 0 J 24,600 J 24,600 J Question 5 A)A 8.43-Newton force was applied for an unknown displacement; however, it is known that 376 joules of work was done. What is the value of the mystery displacement?(1 point) Responses 3170 m 3170 m 44.6 m 44.6 m 368 m 368 m 384 m 384 m
Answers
Answered by
GPT-4o mini
Let's answer each question one at a time.
### Question 1
**A)** What is the mathematical relationship between force and work? (1 point)
**Response:**
The correct equation for work (W) is:
\[ W = F \times d \]
where \( F \) is the force applied, and \( d \) is the displacement in the direction of the force.
### Question 2
**A)** If W = F × d, which of the following equations shows work being calculated using the correct units? (1 point)
To calculate work, we use:
\[ \text{Work (Joules)} = \text{Force (Newtons)} \times \text{Displacement (meters)} \]
**Response:**
The correct equation is:
\[ 113 \, J = (17.4 \, N) \times (6.51 \, m) \]
### Question 3
**A)** A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object? (1 point)
To calculate work:
\[ W = F \times d = 57.1 \, N \times 0.977 \, m \]
Calculating this:
\[ W = 57.1 \times 0.977 \approx 55.8 \, J \]
**Response:**
55.8 J
### Question 4
**A)** A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done? (1 point)
To calculate work:
\[ W = F \times d = 36.8 \, N \times 668 \, m \]
Calculating this:
\[ W = 36.8 \times 668 \approx 24,600.4 \, J \]
**Response:**
24,600 J
### Question 5
**A)** A 8.43-Newton force was applied for an unknown displacement; however, it is known that 376 joules of work was done. What is the value of the mystery displacement? (1 point)
Using the work formula:
\[ W = F \times d \]
We can rearrange it to find displacement:
\[ d = \frac{W}{F} = \frac{376 \, J}{8.43 \, N} \]
Calculating this:
\[ d \approx \frac{376}{8.43} \approx 44.6 \, m \]
**Response:**
44.6 m
If you have any further questions or need clarification on any of the responses, feel free to ask!
### Question 1
**A)** What is the mathematical relationship between force and work? (1 point)
**Response:**
The correct equation for work (W) is:
\[ W = F \times d \]
where \( F \) is the force applied, and \( d \) is the displacement in the direction of the force.
### Question 2
**A)** If W = F × d, which of the following equations shows work being calculated using the correct units? (1 point)
To calculate work, we use:
\[ \text{Work (Joules)} = \text{Force (Newtons)} \times \text{Displacement (meters)} \]
**Response:**
The correct equation is:
\[ 113 \, J = (17.4 \, N) \times (6.51 \, m) \]
### Question 3
**A)** A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object? (1 point)
To calculate work:
\[ W = F \times d = 57.1 \, N \times 0.977 \, m \]
Calculating this:
\[ W = 57.1 \times 0.977 \approx 55.8 \, J \]
**Response:**
55.8 J
### Question 4
**A)** A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done? (1 point)
To calculate work:
\[ W = F \times d = 36.8 \, N \times 668 \, m \]
Calculating this:
\[ W = 36.8 \times 668 \approx 24,600.4 \, J \]
**Response:**
24,600 J
### Question 5
**A)** A 8.43-Newton force was applied for an unknown displacement; however, it is known that 376 joules of work was done. What is the value of the mystery displacement? (1 point)
Using the work formula:
\[ W = F \times d \]
We can rearrange it to find displacement:
\[ d = \frac{W}{F} = \frac{376 \, J}{8.43 \, N} \]
Calculating this:
\[ d \approx \frac{376}{8.43} \approx 44.6 \, m \]
**Response:**
44.6 m
If you have any further questions or need clarification on any of the responses, feel free to ask!