Question

If the reaction shown below were balanced, what would the coefficients be? Al + S --> Al2S3 (1 point) Responses 3Al, 2S, 1Al2S3 3Al, 2S, 1cap A l sub 2 cap s sub 3 2 Al, 3S, 1Al2S3 2 Al, 3S, 1cap A l sub 2 cap s sub 3 3Al, 1S, 2Al2S3 3Al, 1S, 2cap A l sub 2 cap s sub 3 4Al, 6S, 2Al2S3

Answer 1

To balance the reaction \( \text{Al} + \text{S} \rightarrow \text{Al}_2\text{S}_3 \), we need to balance the number of atoms of each element on both sides of the equation.

1. On the right side, \( \text{Al}_2\text{S}_3 \) contains 2 aluminum (Al) atoms and 3 sulfur (S) atoms.

To balance the aluminum atoms:
- We need 2 aluminum atoms, so we place a coefficient of 2 in front of Al:
\[ 2 \text{Al} + \text{S} \rightarrow \text{Al}_2\text{S}_3 \]

2. Now we balance the sulfur atoms:
- We have 3 sulfur atoms in \( \text{Al}_2\text{S}_3 \), so we put a coefficient of 3 in front of S:
\[ 2 \text{Al} + 3 \text{S} \rightarrow \text{Al}_2\text{S}_3 \]

Putting it all together, the balanced reaction is:
\[ 2 \text{Al} + 3 \text{S} \rightarrow 1 \text{Al}_2\text{S}_3 \]

Thus, the coefficients are:
- \( 2 \) for Al
- \( 3 \) for S
- \( 1 \) for \( \text{Al}_2\text{S}_3 \)

The correct response is:
**2 Al, 3 S, 1 Al2S3** (or 2 Al, 3 S, 1 cap A l sub 2 cap s sub 3).