Question

A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point)
Responses

0 J
0 J

24,600 J
24,600 J

705 J
705 J

18.2 J

Answer 1

To calculate the work done by the car, we can use the formula:

\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]

where:
- Work is in joules (J),
- Force is in newtons (N),
- Distance is in meters (m),
- \(\theta\) is the angle between the force and the direction of motion.

Assuming the force is applied in the direction of the movement (which means θ = 0 degrees, and cos(0) = 1), the equation simplifies to:

\[
\text{Work} = \text{Force} \times \text{Distance}
\]

Plugging in the values:

\[
\text{Force} = 36.8 \, \text{N}
\]
\[
\text{Distance} = 668 \, \text{m}
\]

Now, calculate the work done:

\[
\text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} = 24,605.4 \, \text{J}
\]

Rounding to the nearest whole number gives approximately 24,600 J.

Therefore, the correct response is:

**24,600 J**