A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point)

Responses

55.8 J
55.8 J

58.4 J
58.4 J

58.1 J
58.1 J

56.1 J

1 answer

To calculate the work done on an object, you can use the formula:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

where:

  • Work is in joules (J),
  • Force is in newtons (N),
  • Distance is in meters (m),
  • \(\theta\) is the angle between the force and the direction of movement.

Assuming the force is applied in the same direction as the movement (which means \(\theta = 0\) degrees and \(\cos(0) = 1\)), the formula simplifies to:

\[ \text{Work} = \text{Force} \times \text{Distance} \]

Substituting the given values:

\[ \text{Work} = 57.1, \text{N} \times 0.977, \text{m} \]

Calculating this gives:

\[ \text{Work} = 57.1 \times 0.977 \approx 55.8, \text{J} \]

So, the work done on the object is approximately 55.8 J.