To solve the inequality \( 5x + 9 < 8 \), we'll first isolate \( x \).
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Subtract 9 from both sides: \[ 5x < 8 - 9 \] \[ 5x < -1 \]
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Now, divide both sides by 5: \[ x < \frac{-1}{5} \]
The inequality shows that \( x \) is less than \(-\frac{1}{5}\).
To express the improper fraction as a mixed number:
- Since \(-\frac{1}{5}\) is already a proper fraction, it can be represented simply as it is without conversion necessary since it doesn't have a whole number part.
So, the final answer, written with \( x \) first, is: \[ x < -\frac{1}{5} \]