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Use the discriminant to determine how many real-number solutions the equation has. v^2 - 7v + 5 = 0Asked by Don
Use the discriminant to determine how many real number solutions the equation has.
t^2 + 8t + 16 = 0
t^2 + 8t + 16 = 0
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Answered by
Anonymous
discriminant= b2-4ac
(8)^2-4(1)(16)
64-64=0
One real root (because it equals 0).
If it was a positive number, there would be two real roots. If it was a negative number, there would be two COMPLEX roots.
(8)^2-4(1)(16)
64-64=0
One real root (because it equals 0).
If it was a positive number, there would be two real roots. If it was a negative number, there would be two COMPLEX roots.
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