What is the solution of (4 x minus 16) Superscript one-half Baseline = 36?

x = 5
x = 13
x = 20
x = 328

1 answer

To solve the equation \((4x - 16)^{1/2} = 36\), we can start by squaring both sides to eliminate the square root:

\[ (4x - 16) = 36^2 \]

Calculating \(36^2\):

\[ 36^2 = 1296 \]

So now we have:

\[ 4x - 16 = 1296 \]

Next, we add 16 to both sides:

\[ 4x = 1296 + 16 \] \[ 4x = 1312 \]

Now, we divide both sides by 4:

\[ x = \frac{1312}{4} \] \[ x = 328 \]

Thus, the solution is

\[ \boxed{328} \]