Asked by stinkybooty
What is the value of x?
1/2 (8x−6) = x−12
x = ?
1/2 (8x−6) = x−12
x = ?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the equation
\[
\frac{1}{2} (8x - 6) = x - 12,
\]
first, remove the fraction by multiplying both sides of the equation by 2:
\[
8x - 6 = 2(x - 12).
\]
Next, distribute the 2 on the right side:
\[
8x - 6 = 2x - 24.
\]
Now, isolate the variable \(x\) by first moving all terms involving \(x\) to one side and constant terms to the other side. Subtract \(2x\) from both sides:
\[
8x - 2x - 6 = -24.
\]
This simplifies to:
\[
6x - 6 = -24.
\]
Next, add 6 to both sides to isolate the term with \(x\):
\[
6x = -24 + 6,
\]
which simplifies to:
\[
6x = -18.
\]
Finally, divide both sides by 6:
\[
x = -3.
\]
Thus, the value of \(x\) is
\[
\boxed{-3}.
\]
\[
\frac{1}{2} (8x - 6) = x - 12,
\]
first, remove the fraction by multiplying both sides of the equation by 2:
\[
8x - 6 = 2(x - 12).
\]
Next, distribute the 2 on the right side:
\[
8x - 6 = 2x - 24.
\]
Now, isolate the variable \(x\) by first moving all terms involving \(x\) to one side and constant terms to the other side. Subtract \(2x\) from both sides:
\[
8x - 2x - 6 = -24.
\]
This simplifies to:
\[
6x - 6 = -24.
\]
Next, add 6 to both sides to isolate the term with \(x\):
\[
6x = -24 + 6,
\]
which simplifies to:
\[
6x = -18.
\]
Finally, divide both sides by 6:
\[
x = -3.
\]
Thus, the value of \(x\) is
\[
\boxed{-3}.
\]
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