What is the vertex form of the graphed equation with a point of (2,-14)?

1 answer

To express a quadratic equation in vertex form, we use the formula:

\[ y = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola, and \(a\) determines its width and direction (whether it opens upwards or downwards).

From your question, it seems like we have a point \((2, -14)\) on the graph, but we need more information to find the exact vertex form of the quadratic function. Specifically, we need the vertex coordinates \((h, k)\) or the value of \(a\).

If this point is the vertex, we can set \(h = 2\) and \(k = -14\), giving us:

\[ y = a(x - 2)^2 - 14 \]

To determine the value of \(a\), we would need either more points on the graph or additional information about the shape of the parabola (for example, if it passes through another point).

If the point \((2, -14)\) is just a point on the graph but not necessarily the vertex, we'd need the vertex coordinates to proceed further.

Please provide any additional information you have about the quadratic equation or its vertex, and I'll be happy to help you find the complete vertex form!