3 of 53 of 5 Items
Question
Use the image to answer the question.
An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.
Translate figure PQRS
6 units down and 2 units to the right. What are the coordinates of P′
?
(1 point)
Responses
(6, 0)
left parenthesis 6 comma 0 right parenthesis
(2, 0)
left parenthesis 2 comma 0 right parenthesis
(2, 12)
left parenthesis 2 comma 12 right parenthesis
(10, 4)
left parenthesis 10 comma 4 right parenthesis
Skip to navigation
1 answer
To translate the vertex P (which is at coordinates (4, 6)) 6 units down and 2 units to the right:
Move down: From y = 6, moving 6 units down gives us: \[ 6 - 6 = 0 \] So, the y-coordinate is now 0.
Move to the right: From x = 4, moving 2 units to the right gives us: \[ 4 + 2 = 6 \] So, the x-coordinate is now 6.
Therefore, the new coordinates of P′ are (6, 0).
The correct response is: (6, 0)
1 answer
1 answer
1 answer
1 answer