Asked by alex
Now we prove Machin's formula using the tangent addition formula:
tan(A+B)= tanA+tanB/1-tanAtanB.
If A= arctan(120/119) and B= -arctan(1/239), how do you show that
arctan(120/119)-arctan(1/239)=arctan1?
tan(A+B)= tanA+tanB/1-tanAtanB.
If A= arctan(120/119) and B= -arctan(1/239), how do you show that
arctan(120/119)-arctan(1/239)=arctan1?
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