To solve the inequality \( x + \frac{1}{3} > 4 \), we start by isolating \( x \):
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Subtract \( \frac{1}{3} \) from both sides: \[ x > 4 - \frac{1}{3} \]
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Convert \( 4 \) to a fraction with a common denominator (3): \[ 4 = \frac{12}{3} \] So, \[ 4 - \frac{1}{3} = \frac{12}{3} - \frac{1}{3} = \frac{11}{3} \]
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We now have: \[ x > \frac{11}{3} \] which is the same as: \[ x > 3 \frac{2}{3} \]
On a number line, this would be represented as an open circle at \( \frac{11}{3} \) (or \( 3 \frac{2}{3} \)) with a line extending to the right towards positive infinity.
Looking at the options given, the correct graph for the solution \( x > \frac{11}{3} \) is:
A number line with arrows at both ends, an open circle marked above \( 5 \frac{2}{3} \), and a line drawn from the circle toward \( 10 \) with an arrow at the end.
So, if you see an open circle at \( 5 \frac{2}{3} \) with a line extending towards the right (toward positive infinity), that is the correct representation of the solution \( x > \frac{11}{3} \).
None of the provided options correctly match the inequality \( x + \frac{1}{3} > 4 \), so it appears there may be a miscommunication or error in the problem set-up. Make sure to double-check the inequality or the corresponding graphs.