Asked by quandale dingle
Magnitude and Direction of Force Quick Check
4 of 54 of 5 Items
Question
A passenger on a train records a time of 2 minutes for the train to travel 5.2 kilometers along a straight section of track. Which is the train’s average speed in kilometers per hour?(1 point)
Responses
23
23
0.38
0.38
2.6
2.6
156
4 of 54 of 5 Items
Question
A passenger on a train records a time of 2 minutes for the train to travel 5.2 kilometers along a straight section of track. Which is the train’s average speed in kilometers per hour?(1 point)
Responses
23
23
0.38
0.38
2.6
2.6
156
Answers
Answered by
GPT-4o mini
To calculate the train's average speed in kilometers per hour, you can use the formula:
\[
\text{Average Speed} = \frac{\text{Distance}}{\text{Time}}
\]
First, convert the time from minutes to hours. Since there are 60 minutes in an hour, 2 minutes is:
\[
\frac{2 \text{ minutes}}{60 \text{ minutes/hour}} = \frac{1}{30} \text{ hours} \approx 0.0333 \text{ hours}
\]
Now, plug in the values:
\[
\text{Distance} = 5.2 \text{ kilometers}
\]
\[
\text{Time} = \frac{1}{30} \text{ hours}
\]
So the average speed is:
\[
\text{Average Speed} = \frac{5.2 \text{ km}}{\frac{1}{30} \text{ hours}} = 5.2 \text{ km} \times 30 = 156 \text{ km/hour}
\]
Thus, the train's average speed is **156 kilometers per hour**.
\[
\text{Average Speed} = \frac{\text{Distance}}{\text{Time}}
\]
First, convert the time from minutes to hours. Since there are 60 minutes in an hour, 2 minutes is:
\[
\frac{2 \text{ minutes}}{60 \text{ minutes/hour}} = \frac{1}{30} \text{ hours} \approx 0.0333 \text{ hours}
\]
Now, plug in the values:
\[
\text{Distance} = 5.2 \text{ kilometers}
\]
\[
\text{Time} = \frac{1}{30} \text{ hours}
\]
So the average speed is:
\[
\text{Average Speed} = \frac{5.2 \text{ km}}{\frac{1}{30} \text{ hours}} = 5.2 \text{ km} \times 30 = 156 \text{ km/hour}
\]
Thus, the train's average speed is **156 kilometers per hour**.