Question

A particle accelerated by a potential difference enters a velocity selector. The particle travels staright when the magnetic field is 0.400 T and the electric field is 6.30 x 10^5 V/m. Once the electric field is turned off, a sensor determines that the radius or the particle's path is 4.11 cm.

What is the charge to mass ratio of this particle?

This is what i understand..

1) first find the velocity
using formula v =E/B

2) then use q/m = v / B x r

am I right??

Answer 1

q V B = m V^2/r, so

q/m = V/(B*r)

Yes to both questions

Answer 2

thank you =)

Answer 3

Is this particle an electron, proton, alpha particle or non of the above.