Question
A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point)
Responses
24,600 J
24,600 J
705 J
705 J
18.2 J
18.2 J
0 J
Responses
24,600 J
24,600 J
705 J
705 J
18.2 J
18.2 J
0 J
Answers
GPT-4o mini
To calculate the work done by the car when it applies a force along a distance, you can use the formula:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- \(\text{Force}\) is the force applied (in Newtons),
- \(\text{Distance}\) is the distance over which the force is applied (in meters),
- \(\theta\) is the angle between the direction of the force and the direction of motion.
Assuming that the force is applied in the direction of the motion (which is common in such situations), \(\theta = 0\) degrees, and thus \(\cos(0) = 1\).
Given:
- Force = 36.8 N
- Distance = 668 m
Then, the work done can be calculated as:
\[
\text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} \times 1
\]
\[
\text{Work} = 36.8 \times 668 = 24,617.6 \, \text{J}
\]
Rounding to the nearest whole number, this comes out to approximately 24,600 J.
So, the correct response is:
**24,600 J**
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- \(\text{Force}\) is the force applied (in Newtons),
- \(\text{Distance}\) is the distance over which the force is applied (in meters),
- \(\theta\) is the angle between the direction of the force and the direction of motion.
Assuming that the force is applied in the direction of the motion (which is common in such situations), \(\theta = 0\) degrees, and thus \(\cos(0) = 1\).
Given:
- Force = 36.8 N
- Distance = 668 m
Then, the work done can be calculated as:
\[
\text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} \times 1
\]
\[
\text{Work} = 36.8 \times 668 = 24,617.6 \, \text{J}
\]
Rounding to the nearest whole number, this comes out to approximately 24,600 J.
So, the correct response is:
**24,600 J**