Question
The radius of a circle is 20 miles. What is the angle measure of an arc bounding a sector with area 16𝜋 square miles?
K=16𝜋 sq. mi
r=20 mi
Give the exact answer in simplest form.
K=16𝜋 sq. mi
r=20 mi
Give the exact answer in simplest form.
Answers
Answered by
GPT-4o mini
To find the angle measure of an arc bounding a sector with a given area, we can use the formula for the area of a sector of a circle:
\[
A = \frac{1}{2} r^2 \theta
\]
where:
- \( A \) is the area of the sector,
- \( r \) is the radius of the circle,
- \( \theta \) is the angle in radians.
Given:
- \( A = 16\pi \, \text{sq. mi} \)
- \( r = 20 \, \text{mi} \)
We can plug the values into the formula:
\[
16\pi = \frac{1}{2} (20^2) \theta
\]
Calculating \( 20^2 \):
\[
20^2 = 400
\]
Substituting this back into the equation:
\[
16\pi = \frac{1}{2} \cdot 400 \cdot \theta
\]
This simplifies to:
\[
16\pi = 200\theta
\]
Now, solving for \( \theta \):
\[
\theta = \frac{16\pi}{200}
\]
Simplifying this fraction:
\[
\theta = \frac{16\pi}{200} = \frac{16\pi}{100} = \frac{8\pi}{50} = \frac{4\pi}{25}
\]
Thus, the angle measure of the arc bounding the sector is:
\[
\theta = \frac{4\pi}{25} \text{ radians}
\]
This is the exact answer in simplest form.
\[
A = \frac{1}{2} r^2 \theta
\]
where:
- \( A \) is the area of the sector,
- \( r \) is the radius of the circle,
- \( \theta \) is the angle in radians.
Given:
- \( A = 16\pi \, \text{sq. mi} \)
- \( r = 20 \, \text{mi} \)
We can plug the values into the formula:
\[
16\pi = \frac{1}{2} (20^2) \theta
\]
Calculating \( 20^2 \):
\[
20^2 = 400
\]
Substituting this back into the equation:
\[
16\pi = \frac{1}{2} \cdot 400 \cdot \theta
\]
This simplifies to:
\[
16\pi = 200\theta
\]
Now, solving for \( \theta \):
\[
\theta = \frac{16\pi}{200}
\]
Simplifying this fraction:
\[
\theta = \frac{16\pi}{200} = \frac{16\pi}{100} = \frac{8\pi}{50} = \frac{4\pi}{25}
\]
Thus, the angle measure of the arc bounding the sector is:
\[
\theta = \frac{4\pi}{25} \text{ radians}
\]
This is the exact answer in simplest form.
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