Question
n airplane's distance traveled is monitored over time. The results are displayed in this table.
Time (h) 1 2 3 4
Distance traveled (mi) 560 1120 1680 2240
What is the constant of proportionality of this proportional relationship?
Time (h) 1 2 3 4
Distance traveled (mi) 560 1120 1680 2240
What is the constant of proportionality of this proportional relationship?
Answers
Answered by
GPT-4o mini
To find the constant of proportionality in this relationship, we can use the formula for the constant of proportionality, which is the ratio of distance traveled to time.
From the table:
- When \( t = 1 \) hour, distance = 560 miles
- When \( t = 2 \) hours, distance = 1120 miles
- When \( t = 3 \) hours, distance = 1680 miles
- When \( t = 4 \) hours, distance = 2240 miles
To calculate the constant of proportionality (\( k \)), we can compute the ratio of distance to time for any of the time intervals.
Using the first entry:
\[
k = \frac{\text{Distance}}{\text{Time}} = \frac{560 \text{ miles}}{1 \text{ hour}} = 560 \text{ mph}
\]
You can also check using another entry, for example the second entry:
\[
k = \frac{1120 \text{ miles}}{2 \text{ hours}} = 560 \text{ mph}
\]
For the third entry:
\[
k = \frac{1680 \text{ miles}}{3 \text{ hours}} = 560 \text{ mph}
\]
For the fourth entry:
\[
k = \frac{2240 \text{ miles}}{4 \text{ hours}} = 560 \text{ mph}
\]
Thus, the constant of proportionality in this relationship is \( **560 \text{ mph}** \).
From the table:
- When \( t = 1 \) hour, distance = 560 miles
- When \( t = 2 \) hours, distance = 1120 miles
- When \( t = 3 \) hours, distance = 1680 miles
- When \( t = 4 \) hours, distance = 2240 miles
To calculate the constant of proportionality (\( k \)), we can compute the ratio of distance to time for any of the time intervals.
Using the first entry:
\[
k = \frac{\text{Distance}}{\text{Time}} = \frac{560 \text{ miles}}{1 \text{ hour}} = 560 \text{ mph}
\]
You can also check using another entry, for example the second entry:
\[
k = \frac{1120 \text{ miles}}{2 \text{ hours}} = 560 \text{ mph}
\]
For the third entry:
\[
k = \frac{1680 \text{ miles}}{3 \text{ hours}} = 560 \text{ mph}
\]
For the fourth entry:
\[
k = \frac{2240 \text{ miles}}{4 \text{ hours}} = 560 \text{ mph}
\]
Thus, the constant of proportionality in this relationship is \( **560 \text{ mph}** \).