Points upper A upper C mark the ends of a line segment that slopes upward from left to right. Point upper B is at the midpoint. Identical single hash marks are between upper A and upper B and between upper B and upper C.

Nozomi constructed a copy of AB¯¯¯¯¯¯¯¯
by using point B
as an endpoint of the copy of AB¯¯¯¯¯¯¯¯
and placing point C
, as seen in the image. If the measure of AB¯¯¯¯¯¯¯¯
is 22.3 millimeters, what is the measure of AC¯¯¯¯¯¯¯¯
?

(1 point)
Responses

The measure of AC¯¯¯¯¯¯¯¯
is 66.9 millimeters.
The measure of Modifying above upper A upper C with bar is 66.9 millimeters.

The measure of AC¯¯¯¯¯¯¯¯
is 22.3 millimeters.
The measure of Modifying above upper A upper C with bar is 22.3 millimeters.

The measure of AC¯¯¯¯¯¯¯¯
is 44.6 millimeters.
The measure of Modifying above upper A upper C with bar is 44.6 millimeters.

The measure of AC¯¯¯¯¯¯¯¯
is 11.15 millimeters.
The measure of Modifying above upper A upper C with bar is 11.15 millimeters.
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1 answer

To find the measure of \( \overline{AC} \), we need to understand how the points A, B, and C are related in terms of length.

  1. Point B is the midpoint of segment \( \overline{AC} \). This means that \( AB = BC \).
  2. Given that the measure of \( \overline{AB} \) is 22.3 millimeters, we can calculate \( AC \) by using the relationship: \[ AC = AB + BC = AB + AB = 2 \times AB \]

Given that \( AB = 22.3 \) mm:

\[ AC = 2 \times 22.3 = 44.6 \text{ mm} \]

Therefore, the measure of \( \overline{AC} \) is 44.6 millimeters.

The correct response would be: The measure of \( \overline{AC} \) is 44.6 millimeters.