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When Jason left his house this morning, his cell phone was 40% charged and it then started to lose 4% charge for each hour thereafter. Write an equation for B, commaB, in terms of t, commat, representing the charge remaining in Jason's battery, as a percentage, tt hours after Jason left his house.
Number of Hours Since Jason Left His House Percentage Charge Remaining on Phone Battery
00
11
22
33
Watch Video
Show Examples
When Jason left his house this morning, his cell phone was 40% charged and it then started to lose 4% charge for each hour thereafter. Write an equation for B, commaB, in terms of t, commat, representing the charge remaining in Jason's battery, as a percentage, tt hours after Jason left his house.
Number of Hours Since Jason Left His House Percentage Charge Remaining on Phone Battery
00
11
22
33
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Answered by
GPT-4o mini
To represent the charge remaining in Jason's battery as a percentage after \( t \) hours, we can use the following equation:
\[
B(t) = 40 - 4t
\]
Where:
- \( B(t) \) is the battery percentage remaining after \( t \) hours.
- 40 represents the initial charge percentage when Jason left his house.
- \( 4t \) represents the amount of charge lost, calculated at a rate of 4% per hour.
Next, we can fill in the table with values for \( t = 0, 1, 2, \) and \( 3 \) hours:
| Number of Hours Since Jason Left His House | Percentage Charge Remaining on Phone Battery |
|--------------------------------------------|---------------------------------------------|
| 0 | \( B(0) = 40 - 4(0) = 40 \) |
| 1 | \( B(1) = 40 - 4(1) = 36 \) |
| 2 | \( B(2) = 40 - 4(2) = 32 \) |
| 3 | \( B(3) = 40 - 4(3) = 28 \) |
So the completed table looks like this:
| Number of Hours Since Jason Left His House | Percentage Charge Remaining on Phone Battery |
|--------------------------------------------|---------------------------------------------|
| 0 | 40 |
| 1 | 36 |
| 2 | 32 |
| 3 | 28 |
\[
B(t) = 40 - 4t
\]
Where:
- \( B(t) \) is the battery percentage remaining after \( t \) hours.
- 40 represents the initial charge percentage when Jason left his house.
- \( 4t \) represents the amount of charge lost, calculated at a rate of 4% per hour.
Next, we can fill in the table with values for \( t = 0, 1, 2, \) and \( 3 \) hours:
| Number of Hours Since Jason Left His House | Percentage Charge Remaining on Phone Battery |
|--------------------------------------------|---------------------------------------------|
| 0 | \( B(0) = 40 - 4(0) = 40 \) |
| 1 | \( B(1) = 40 - 4(1) = 36 \) |
| 2 | \( B(2) = 40 - 4(2) = 32 \) |
| 3 | \( B(3) = 40 - 4(3) = 28 \) |
So the completed table looks like this:
| Number of Hours Since Jason Left His House | Percentage Charge Remaining on Phone Battery |
|--------------------------------------------|---------------------------------------------|
| 0 | 40 |
| 1 | 36 |
| 2 | 32 |
| 3 | 28 |
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