To find the y-intercept of the function \( y = 2x + 1 \), we evaluate the function when \( x = 0 \):
\[ y = 2(0) + 1 = 1. \]
Thus, the y-intercept of the function \( y = 2x + 1 \) is \( (0, 1) \).
Now, let's analyze the line running through the points (-3, -1) and (6, 5) in the graph.
First, we can find the slope of the line using the formula:
\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - (-1)}{6 - (-3)} = \frac{5 + 1}{6 + 3} = \frac{6}{9} = \frac{2}{3}. \]
Next, we can use one of the points (let's take -3, -1) to find the equation of the line using the point-slope form \( y - y_1 = m(x - x_1) \):
\[ y - (-1) = \frac{2}{3}(x - (-3)) \implies y + 1 = \frac{2}{3}(x + 3). \]
To convert this to slope-intercept form, distribute and simplify:
\[ y + 1 = \frac{2}{3}x + 2 \implies y = \frac{2}{3}x + 2 - 1 \implies y = \frac{2}{3}x + 1. \]
Now we can find the y-intercept of this line:
For \( x = 0 \):
\[ y = \frac{2}{3}(0) + 1 = 1, \]
which gives the y-intercept at \( (0, 1) \).
Both functions have the same y-intercept of \( 1 \).
Thus, you can complete the statement as follows:
The y-intercept of the function \( y = 2x + 1 \) is equal to the y-intercept of the function represented in the graph.