Question

Select the best set of coefficients to completely balance the following equation:

Lead (II) nitrate + potassium iodide ---> potassium nitrate + lead (II) iodide
_Pb(NO3)2 + __Kl ---> __KNO3 + __PbI2

(1 point)
Responses

1, 3, 3, 1
1, 3, 3, 1

2, 3, 3, 2
2, 3, 3, 2

1, 2, 2, 1
1, 2, 2, 1

1, 2, 1, 2

Answer 1

To balance the chemical equation for the reaction of Lead (II) nitrate and Potassium iodide, let's start with the unbalanced equation:

\[ \text{Pb(NO}_3\text{)}_2 + \text{KI} \rightarrow \text{KNO}_3 + \text{PbI}_2 \]

1. On the left side, we have:
- 1 Pb (Lead)
- 2 NO3 (Nitrates)
- 1 K (Potassium)
- 1 I (Iodine)

2. On the right side, we also find:
- 1 Pb (Lead)
- 1 K (Potassium)
- 1 NO3 (Nitrate)
- 2 I (Iodine)

To balance the equation, we need to ensure that we have the same number of each type of atom on both sides.

- For Potassium (K), we see there is 1 on each side initially, but we will need to account for the 2 Iodines from Lead (II) iodide, which means we will need 2 K on the reactant side for the 2 KNO3 produced.
- Therefore, we need to have 2 K on the left side.

Next, adjust for Nitrogen and Oxygen:
- If we have 2 KI (which gives us 2 K) on the left, this means we will produce 2 KNO3 on the right because each KI provides 1 K.

Given these, let's rewrite what we suspect the correct coefficients should be:
- Lead (II) nitrate: 1
- Potassium iodide: 2
- Potassium nitrate: 2
- Lead (II) iodide: 1

So the balanced equation will be:

\[ \text{1 Pb(NO}_3\text{)}_2 + \text{2 KI} \rightarrow \text{2 KNO}_3 + \text{1 PbI}_2 \]

Thus, the coefficients are:

**1, 2, 2, 1**

From the provided options, this matches with **1, 2, 2, 1**.

So the answer is:

**1, 2, 2, 1**