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Question
How long would you have to film something in HD to collect 1 PB of data?

(1 point)
Responses

all day for 2 consecutive weeks

all day for 2 consecutive weeks

all day for 365 days (or 364 days in a leap year)

all day for 365 days (or 364 days in a leap year)

all day for about 3.5 years

all day for about 3.5 years

all day for one light year

all day for one light year
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Answers

Answered by GPT-4o mini
To determine how long you would need to film in HD to accumulate 1 petabyte (PB) of data, we need to know the typical data rate for HD video.

1. **HD Video Bitrates**:
- Let's consider a common bitrate for HD video (1080p) which is around 5 Mbps (megabits per second) for streaming. Note that higher-quality formats (such as 4K) will have much higher bitrates.

2. **Convert to Bytes**:
- 5 Mbps is equivalent to \( 5 \times 10^6 \) bits per second.
- To convert bits to bytes, divide by 8:
\[
5,000,000 \text{ bits/second} \div 8 = 625,000 \text{ bytes/second}
\]

3. **Calculate PB in Bytes**:
- 1 PB (petabyte) = \( 1 \times 10^{15} \) bytes.

4. **Calculate the Time to Collect 1 PB**:
- To find out how long it takes to reach 1 PB at 625,000 bytes/second:
\[
\text{time in seconds} = \frac{1 \times 10^{15} \text{ bytes}}{625,000 \text{ bytes/second}} \approx 1.6 \times 10^9 \text{ seconds}
\]

5. **Convert to Days**:
- There are 86,400 seconds in a day:
\[
\text{time in days} = \frac{1.6 \times 10^9 \text{ seconds}}{86,400 \text{ seconds/day}} \approx 18,518 \text{ days}
\]

6. **Convert to Years**:
- To convert to years, divide by 365:
\[
\text{time in years} = \frac{18,518 \text{ days}}{365 \text{ days/year}} \approx 50.7 \text{ years}
\]

Thus, to collect 1 PB of data filming in HD at 5 Mbps, you would need to film for **about 50.7 years**, assuming continuous recording without any interruptions.

Looking at the options provided, none of these clearly represent this calculation accurately. Ensure to check the video bitrate used in the context of this question, as different compression methods and resolutions can dramatically affect the data rate and the resulting time frame.

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