Asked by quandale dingle
Question
Use the image to answer the question.
A graph shows four quadrants with the x-axis and y-axis both ranging from negative 5 to positive 5 in increments of 1. Unlabeled data points marked are at left parenthesis negative 2 comma negative 1 right parenthesis, and at left parenthesis 2 comma 4 right parenthesis. A straight line joins the two lines with a positive slope.
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
41
41
9
9
6:40
6:40
5.57
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the distance between the two points \((-2, -1)\) and \((2, 4)\), we can use the distance formula, which is derived from the Pythagorean theorem:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-2, -1)\) and \((x_2, y_2) = (2, 4)\).
Now, let's plug in the values:
1. Calculate \(x_2 - x_1\):
\[
2 - (-2) = 2 + 2 = 4
\]
2. Calculate \(y_2 - y_1\):
\[
4 - (-1) = 4 + 1 = 5
\]
3. Now apply these to the distance formula:
\[
d = \sqrt{(4)^2 + (5)^2} = \sqrt{16 + 25} = \sqrt{41}
\]
Finally, we need to find the approximate value of \(\sqrt{41}\):
\[
\sqrt{41} \approx 6.403124237
\]
Rounding to the nearest hundredth, the distance \(d\) is approximately \(6.40\).
So, the correct answer is:
**6:40**
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-2, -1)\) and \((x_2, y_2) = (2, 4)\).
Now, let's plug in the values:
1. Calculate \(x_2 - x_1\):
\[
2 - (-2) = 2 + 2 = 4
\]
2. Calculate \(y_2 - y_1\):
\[
4 - (-1) = 4 + 1 = 5
\]
3. Now apply these to the distance formula:
\[
d = \sqrt{(4)^2 + (5)^2} = \sqrt{16 + 25} = \sqrt{41}
\]
Finally, we need to find the approximate value of \(\sqrt{41}\):
\[
\sqrt{41} \approx 6.403124237
\]
Rounding to the nearest hundredth, the distance \(d\) is approximately \(6.40\).
So, the correct answer is:
**6:40**
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