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Question Apply the Pythagorean Theorem to find the length between (2, 5) and (7, 3) . Round your answer to the nearest hundredt...Asked by quandale dingle
Question
Apply the Pythagorean Theorem to find the length between (2, 5)
and (7, 3)
. Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
29
29
4.58
4.58
2.65
2.65
5.39
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the length between the points \( (2, 5) \) and \( (7, 3) \), we can use the distance formula, which is derived from the Pythagorean Theorem:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, let \( (x_1, y_1) = (2, 5) \) and \( (x_2, y_2) = (7, 3) \).
Now, substitute the values into the formula:
\[
d = \sqrt{(7 - 2)^2 + (3 - 5)^2}
\]
\[
d = \sqrt{(5)^2 + (-2)^2}
\]
\[
d = \sqrt{25 + 4}
\]
\[
d = \sqrt{29}
\]
Now, we can calculate \( \sqrt{29} \):
\[
\sqrt{29} \approx 5.385
\]
Rounding this to the nearest hundredth gives:
\[
d \approx 5.39
\]
Thus, the length between the points \( (2, 5) \) and \( (7, 3) \) is approximately **5.39**.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, let \( (x_1, y_1) = (2, 5) \) and \( (x_2, y_2) = (7, 3) \).
Now, substitute the values into the formula:
\[
d = \sqrt{(7 - 2)^2 + (3 - 5)^2}
\]
\[
d = \sqrt{(5)^2 + (-2)^2}
\]
\[
d = \sqrt{25 + 4}
\]
\[
d = \sqrt{29}
\]
Now, we can calculate \( \sqrt{29} \):
\[
\sqrt{29} \approx 5.385
\]
Rounding this to the nearest hundredth gives:
\[
d \approx 5.39
\]
Thus, the length between the points \( (2, 5) \) and \( (7, 3) \) is approximately **5.39**.
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