A right triangle has a hypotenuse of length 18 and an angle of 35°, with a side opposite this angle of length 4. A second right triangle also has an angle of 35°, with a hypotenuse of length 9. Determine the length of the side opposite the 35° angle on the second triangle.(1 point) units

1 answer

In a right triangle, the length of the side opposite an angle can be determined using the sine function. The sine of an angle in a right triangle is defined as the ratio of the length of the opposite side to the length of the hypotenuse:

\[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \]

For the first triangle, we have:

\[ \sin(35^\circ) = \frac{4}{18} \]

Now, we can calculate the sine of \(35^\circ\):

First, calculate:

\[ \frac{4}{18} = \frac{2}{9} \]

Thus,

\[ \sin(35^\circ) \approx 0.5736 \quad (\text{using a calculator}) \]

This means that the sine of \(35^\circ\) matches our earlier calculation. Now let's use this value for the second triangle which has a hypotenuse of \(9\) and we want to find the opposite side:

Using the sine formula again:

\[ \sin(35^\circ) = \frac{\text{opposite}}{9} \]

Now plug in the value of \(\sin(35^\circ)\):

\[ 0.5736 = \frac{\text{opposite}}{9} \]

To find the length of the side opposite the \(35^\circ\) angle, we multiply both sides by \(9\):

\[ \text{opposite} = 9 \times 0.5736 \approx 5.1624 \]

Thus, the length of the side opposite the \(35^\circ\) angle in the second triangle is approximately:

\[ \boxed{5.16} \text{ units} \]