Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Use the Pythagorean Theorem Practice Complete this assessment to review what you've learned. It will not count toward your grad...Asked by quandale dingle
Use the Pythagorean Theorem Practice
Complete this assessment to review what you've learned. It will not count toward your grade.
1 of 51 of 5 Items
Question
If a right triangle has a leg that is 6 ft. long and the hypotenuse is 12 ft. long, how long is the other leg? Round to the nearest tenth.(1 point)
ft.
Remaining Attempts : 3
Complete this assessment to review what you've learned. It will not count toward your grade.
1 of 51 of 5 Items
Question
If a right triangle has a leg that is 6 ft. long and the hypotenuse is 12 ft. long, how long is the other leg? Round to the nearest tenth.(1 point)
ft.
Remaining Attempts : 3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the length of the other leg of a right triangle using the Pythagorean Theorem, you can use the formula:
\[ a^2 + b^2 = c^2 \]
where \( c \) is the length of the hypotenuse, and \( a \) and \( b \) are the lengths of the legs. In this case, you know one leg (\( a = 6 \) ft) and the hypotenuse (\( c = 12 \) ft). You need to find the other leg (\( b \)).
Plugging in the values:
\[ 6^2 + b^2 = 12^2 \]
Calculating the squares:
\[ 36 + b^2 = 144 \]
Now subtract 36 from both sides:
\[ b^2 = 144 - 36 \]
\[ b^2 = 108 \]
Next, take the square root of both sides to find \( b \):
\[ b = \sqrt{108} \]
To simplify \( \sqrt{108} \):
\[ \sqrt{108} = \sqrt{36 \cdot 3} = 6\sqrt{3} \]
Now, calculating \( 6\sqrt{3} \) gives approximately:
\[ 6 \times 1.732 \approx 10.392 \]
Rounding to the nearest tenth:
The length of the other leg is approximately **10.4 ft**.
\[ a^2 + b^2 = c^2 \]
where \( c \) is the length of the hypotenuse, and \( a \) and \( b \) are the lengths of the legs. In this case, you know one leg (\( a = 6 \) ft) and the hypotenuse (\( c = 12 \) ft). You need to find the other leg (\( b \)).
Plugging in the values:
\[ 6^2 + b^2 = 12^2 \]
Calculating the squares:
\[ 36 + b^2 = 144 \]
Now subtract 36 from both sides:
\[ b^2 = 144 - 36 \]
\[ b^2 = 108 \]
Next, take the square root of both sides to find \( b \):
\[ b = \sqrt{108} \]
To simplify \( \sqrt{108} \):
\[ \sqrt{108} = \sqrt{36 \cdot 3} = 6\sqrt{3} \]
Now, calculating \( 6\sqrt{3} \) gives approximately:
\[ 6 \times 1.732 \approx 10.392 \]
Rounding to the nearest tenth:
The length of the other leg is approximately **10.4 ft**.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.