To find the point where the graph of the equation \( y = \left(x - \frac{3}{2}\right)^2 + \frac{5}{4} \) crosses the y-axis, we set \( x = 0 \) because the y-axis corresponds to the value of \( x \) being zero.
Now we can substitute \( x = 0 \) into the equation:
\[ y = \left(0 - \frac{3}{2}\right)^2 + \frac{5}{4} \]
Calculating this step-by-step:
- Compute \( 0 - \frac{3}{2} = -\frac{3}{2} \).
- Square it: \[ \left(-\frac{3}{2}\right)^2 = \frac{9}{4} \]
- Now, substitute back into the equation: \[ y = \frac{9}{4} + \frac{5}{4} \]
- Combine the fractions: \[ y = \frac{9 + 5}{4} = \frac{14}{4} = \frac{7}{2} \]
Thus, the graph crosses the y-axis at:
\[ y = \frac{7}{2} \]
So the answer is \( y = \frac{7}{2} \).