Subtract 3x from each side to get rid of 3x on the left and maintain balance.

2
1

(6x−10)
=
7x+15

3x − 5
=
7x + 15

3x

3x

=

1 answer

Let's start from the equation you provided:

\[ \frac{6x - 10}{2} = 7x + 15 \]

First, to eliminate the fraction, multiply both sides by 2:

\[ 6x - 10 = 2(7x + 15) \]

Now simplify the right side:

\[ 6x - 10 = 14x + 30 \]

Next, subtract \(3x\) from each side as you instructed. We will first rearrange the equation to have \(x\) terms on one side:

\[ 6x - 10 - 3x = 14x + 30 - 3x \]

This simplifies to:

\[ (6x - 3x) - 10 = (14x - 3x) + 30 \]

That leads us to:

\[ 3x - 10 = 11x + 30 \]

Now we can isolate \(x\) by completing the equation. We will subtract \(11x\) from both sides:

\[ 3x - 11x - 10 = 30 \]

This simplifies to:

\[ -8x - 10 = 30 \]

Next, add 10 to both sides:

\[ -8x = 40 \]

Now divide by \(-8\):

\[ x = -5 \]

So, the solution to the equation is:

\[ x = -5 \]