Tristan is in charge of cheerleading tryouts for their school. They need to pick 12 new cheerleaders to allocate across both the varsity and junior varsity squads. Which of the following is a viable solution? (1 point)

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URSE TOOLS
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• 15 varsity cheerleaders and -3 junior varsity cheerleaders
• 8 varsity cheerleaders and 8 junior varsity cheerleaders
• 0 varsity cheerleaders and 12 junior varsity cheerleaders
• 8 varsity cheerleaders and 4 junior varsity cheerleaders

Choose one answer that’s most for

1 answer

To determine a viable solution for allocating 12 new cheerleaders between varsity and junior varsity squads, we can analyze each option:

  1. 15 varsity cheerleaders and -3 junior varsity cheerleaders: This option is not viable, as it would result in a negative number of junior varsity cheerleaders.

  2. 8 varsity cheerleaders and 8 junior varsity cheerleaders: This option totals 16 cheerleaders, which exceeds the required 12, so it is not feasible.

  3. 0 varsity cheerleaders and 12 junior varsity cheerleaders: This option totals 12 cheerleaders, which is exactly what is needed, making it a viable solution.

  4. 8 varsity cheerleaders and 4 junior varsity cheerleaders: This option adds up to 12 cheerleaders, which is also a viable solution.

Given the requirement to choose one viable solution, both the third and fourth options are feasible. However, if you need to pick just one, the 0 varsity cheerleaders and 12 junior varsity cheerleaders solution is a straightforward allocation that meets the criteria.

Therefore, the best answer would be: 0 varsity cheerleaders and 12 junior varsity cheerleaders.