Question
You are rolling a number cube to help you pick the number of minutes you will run in each of your workout sets. Determine the probability of rolling an odd number three times in a row.(1 point)
Responses
18
Start Fraction 1 over 8 End Fraction
1216
Start Fraction 1 over 216 End Fraction
12
Start Fraction 1 over 2 End Fraction
32
Start Fraction 3 over 2 End Fraction
Responses
18
Start Fraction 1 over 8 End Fraction
1216
Start Fraction 1 over 216 End Fraction
12
Start Fraction 1 over 2 End Fraction
32
Start Fraction 3 over 2 End Fraction
Answers
GPT-4o mini
To determine the probability of rolling an odd number three times in a row on a standard number cube (which has sides numbered 1 through 6), we first find the probability of rolling an odd number in a single roll.
The odd numbers on a number cube are: 1, 3, and 5. Therefore, there are 3 odd numbers out of 6 total numbers.
The probability \( P \) of rolling an odd number in one roll is:
\[
P(\text{odd}) = \frac{3}{6} = \frac{1}{2}
\]
Now, we want the probability of this event happening three times in a row. Since the rolls are independent, we multiply the probabilities:
\[
P(\text{odd three times}) = P(\text{odd}) \times P(\text{odd}) \times P(\text{odd}) = \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^3 = \frac{1}{8}
\]
Thus, the probability of rolling an odd number three times in a row is:
\[
\frac{1}{8}
\]
So the correct response is:
**Start Fraction 1 over 8 End Fraction**
The odd numbers on a number cube are: 1, 3, and 5. Therefore, there are 3 odd numbers out of 6 total numbers.
The probability \( P \) of rolling an odd number in one roll is:
\[
P(\text{odd}) = \frac{3}{6} = \frac{1}{2}
\]
Now, we want the probability of this event happening three times in a row. Since the rolls are independent, we multiply the probabilities:
\[
P(\text{odd three times}) = P(\text{odd}) \times P(\text{odd}) \times P(\text{odd}) = \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^3 = \frac{1}{8}
\]
Thus, the probability of rolling an odd number three times in a row is:
\[
\frac{1}{8}
\]
So the correct response is:
**Start Fraction 1 over 8 End Fraction**