Calculate simple interest on $1000 investment with interest rate of 10% a yr after 2 months

1 answer

To calculate simple interest, you can use the formula:

\[ \text{Simple Interest} = P \times r \times t \]

where:

  • \( P \) is the principal amount (the initial investment),
  • \( r \) is the annual interest rate (expressed as a decimal),
  • \( t \) is the time the money is invested for (in years).

In this case:

  • \( P = 1000 \)
  • \( r = 10% = 0.10 \)
  • \( t = \frac{2}{12} \) years (since 2 months is \( \frac{2}{12} \) of a year or \( \frac{1}{6} \) of a year).

Now, plug the values into the formula:

\[ \text{Simple Interest} = 1000 \times 0.10 \times \frac{2}{12} \]

Calculating this step by step:

  1. First, calculate \( \frac{2}{12} \):

\[ \frac{2}{12} = \frac{1}{6} \approx 0.1667 \]

  1. Now, substitute this value back into the equation:

\[ \text{Simple Interest} = 1000 \times 0.10 \times 0.1667 \]

  1. Calculate \( 1000 \times 0.10 = 100 \):

\[ \text{Simple Interest} = 100 \times 0.1667 \approx 16.67 \]

Therefore, the simple interest earned on a $1000 investment at a 10% annual interest rate after 2 months is approximately $16.67.