Asked by Keaton
3/2y-3/2y+4
could you help me please
could you help me please
Answers
Answered by
drwls
You have not explained what the problem is. You have also not clarified whether the first and second terms are (3/2)y or 3/(2y)
It might help to realize that
3/(2y) - 3/(2y) = 0
It might help to realize that
3/(2y) - 3/(2y) = 0
Answered by
Keaton
What happen to the 4 because the problem is 3 over 2y minus -3 over 2y+4= what. so what happen to the four
Answered by
Keaton
3/2y-3/2y+4
help me I must turn in tonight.
help me I must turn in tonight.
Answered by
drwls
You should have written the "problem" with parentheses as
3/(2y) -3/(2y+4) . The way you wrote it, it is not clear what the denomonators are.
You still have not asked a question.
You cannot solve for y since it is not an equation. If you are supposed to rewite it with a common deominator, that would be
3(2y+4)-3(2y)/[2y(2y+4)]
= 12/[2y(2y+4)] = 6/[y(2y+4)]
3/(2y) -3/(2y+4) . The way you wrote it, it is not clear what the denomonators are.
You still have not asked a question.
You cannot solve for y since it is not an equation. If you are supposed to rewite it with a common deominator, that would be
3(2y+4)-3(2y)/[2y(2y+4)]
= 12/[2y(2y+4)] = 6/[y(2y+4)]
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